Math
posted by Allessandra .
Differentiate
(1 sinx) / (1 +sinx)
How would I do this?
The answer is (2cosx)/ (1 + sinx)^2
Thanks in advance :)!!

d/dx (1sinx)/(1+sinx)
[cosx (1+sinx)  (1sinx)(cosx)]/(1+sinx)^2
(cosx  sinx cosx  cosx + sinx cosx)/(1+sinx)^2
= 2cosx/(1+sinx)^2