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Quadrilateral JKLM is a rhombus. The diagonals intersect at N. If angle KNJ equals 8x + 6, find the value of x

  • geometry -

    N is the center of symmetry of the rhombus. The diagonals intersect to form 4 right angles (because the figure is a rhombus).

    KNJ is a right angle
    Therefore 90 = 8x + 6 (degrees)
    8x = 84
    x = 10.5

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