Posted by Piper on .
Quadrilateral JKLM is a rhombus. The diagonals intersect at N. If angle KNJ equals 8x + 6, find the value of x
N is the center of symmetry of the rhombus. The diagonals intersect to form 4 right angles (because the figure is a rhombus).
KNJ is a right angle
Therefore 90 = 8x + 6 (degrees)
8x = 84
x = 10.5