Posted by **95** on Friday, December 16, 2011 at 8:22pm.

what is the directrix and focus of the equation 1/16(y+4)^2=x-3

- precalc -
**Steve**, Saturday, December 17, 2011 at 12:34am
The parabola y = 1/4d x^2 has

vertex at (0,0)

focal distance = d

focus at (0,1)

directrix y = -1

Now we have transformed our equation to

(x-3) = 1/4*4 (y+4)^2

with

vertex at (3,-4)

focal distance = 4

focus at (7,-4)

directrix x = -1

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