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March 24, 2017

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what is the directrix and focus of the equation 1/16(y+4)^2=x-3

  • precalc - ,

    The parabola y = 1/4d x^2 has

    vertex at (0,0)
    focal distance = d
    focus at (0,1)
    directrix y = -1

    Now we have transformed our equation to

    (x-3) = 1/4*4 (y+4)^2
    with
    vertex at (3,-4)
    focal distance = 4
    focus at (7,-4)
    directrix x = -1

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