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April 19, 2014

April 19, 2014

Posted by **95** on Friday, December 16, 2011 at 1:33pm.

Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.

- precalc -
**Reiny**, Friday, December 16, 2011 at 1:53pm3(y^2 + 2y + ...) - 969 = -108x

3(y^2 + 2y + 1) - 969 - 3 = -108x

3(y+1)^2 - 972 = -108x

(-1/36) (y+1)^2 + 9 = x

I will assume you realize that this is a "horizontal" parabola and that you know how to read the vertex from that form.

- precalc -
**Reiny**, Friday, December 16, 2011 at 1:56pmJust realized that Steve had already answered this question before you reposted it

http://www.jiskha.com/display.cgi?id=1324054249

Have patience and always check if your question has been answered before re-posting it.

It saves unnecessary work on our part.

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