Posted by **95** on Friday, December 16, 2011 at 1:33pm.

Parabola:

Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.

- precalc -
**Reiny**, Friday, December 16, 2011 at 1:53pm
3(y^2 + 2y + ...) - 969 = -108x

3(y^2 + 2y + 1) - 969 - 3 = -108x

3(y+1)^2 - 972 = -108x

(-1/36) (y+1)^2 + 9 = x

I will assume you realize that this is a "horizontal" parabola and that you know how to read the vertex from that form.

- precalc -
**Reiny**, Friday, December 16, 2011 at 1:56pm
Just realized that Steve had already answered this question before you reposted it

http://www.jiskha.com/display.cgi?id=1324054249

Have patience and always check if your question has been answered before re-posting it.

It saves unnecessary work on our part.

## Answer this Question

## Related Questions

- precalc - Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.
- Parabolas in standard form! - Hello, I am having the worst time trying to solve ...
- precalc - write 196x^2-256y^2+17=12561 in standard form, show work.
- Parabola - How do I put this parabola in standard form? Could someone show how ...
- precalc - find an equation of the tangent line to the parabola at the given ...
- Precalc - How would I put this parabola in standard form: x^2-6x+8y-31 Here how ...
- Physics - A circuit contains a self-inductance L in series with a capacitor C ...
- Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...
- Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...
- algebra 2 - Determine values for A, B, and C such that the equation below ...

More Related Questions