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July 23, 2014

July 23, 2014

Posted by **Donielle** on Friday, December 16, 2011 at 12:11pm.

x^2-1=(x-1)(x+1)

x^3-1=(x-1)(x^2+x+1)

x^4-1=(x-1)(x^3+x^2+x+1)

In general, how can x^n-1 be factored. Show that this factorization works by multiplying the factors

- Algebra 2 -
**drwls**, Friday, December 16, 2011 at 7:25pmIt should be obvious from the examples that

x^n - 1 =

(x-1)[x^(n-1) + x^(n-2) .. x + 1]

The series in the second factor stops when the last term => x^0 = 1

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