Wednesday

March 4, 2015

March 4, 2015

Posted by **95** on Friday, December 16, 2011 at 11:50am.

- precalc -
**Steve**, Friday, December 16, 2011 at 1:27pmThat's pretty much in standard form.

ax^2 + bxy + cy^2 + dx + ey + f = 0

3y^2 + 108x + 6y - 969 = 0

Now if you want a "standard" form for a parabola x-h = a(y-k)^2, try this:

108x = -3y^2 - 6y + 969

108x = -3(y^2 + 2y + 1) + 972

x = -1/36 (y+1)^2 + 9

**Answer this Question**

**Related Questions**

precalc - Parabola: Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work...

Parabolas in standard form! - Hello, I am having the worst time trying to solve ...

precalc - write 196x^2-256y^2+17=12561 in standard form, show work.

Physics - A circuit contains a self-inductance L in series with a capacitor C ...

physics - A square loop (side L) spins with angular frequency ω in field of...

Math - Find and express the results in polar form for the following: z = 2(e^(-j...

Trig?Precalc - write the rectangular equation x^2+y^2=6 in polar form. I do not ...

Physics - A particle executes simple harmonic motion with an amplitude of 9.00 ...

physics - A horizontal spring mass system is set up to keep time so that it goes...

Trig/PreCalc - Teach me how to express 5sqrt3 - 5i in polar form please. I don't...