Posted by **Donielle** on Friday, December 16, 2011 at 11:10am.

Look at the following polynomials and their factorizations:

x^2-1=(x-1)(x+1)

x^3-1=(x-1)(x^2+x+1)

x^4-1=(x-1)(x^3+x^2+x+1)

In general, how can x^n-1 be factored. Show that this factorization works by multiplying the factors

## Answer this Question

## Related Questions

- Algebra 2 - Look at the following polynomials and their factorizations: x^2-1=(x...
- math - each of the natural numbers 2 through 100, inclusive, is factored in its ...
- Maths - 1) Factorise x2 -6x +8 (the 2 is squared) 2) Hence solve this equation: ...
- Algebra I - Multiplying Polynomials...... Do you have a question? Use the ...
- math - Factor 2x+13x+40 I thought with this sort of problem you are supposed to...
- algebra 2 - Factor completely with respect to the integers. 1. 9x^2 - 4 2. x^3...
- algebra - Consider the following four polynomials, labeled A - D: A. ( 2x2 - 4x...
- math - describe general rule for which fraction that have decimal forms that ...
- factoring - can this equation be factored further? y= x^4+2x^3+4x^2+8x+16 Not in...
- college-Linear Algebra - Let V={f(x)=c0 + c1x + c2x2 : 01 f(x)dx=1}. In other ...