posted by Cha-Ching on .
A 47.5g sample of metal is heated to 300.0ºC and placed in a calorimeter containing 75.0g water at 22.0ºC. The final temperature of the system is 40.0ºC. What is the specific heat of the metal? (the specific heat of water is 4.18 J/g ºC)
Thanks for your time helping!
The heat lost by the metal is the heat gained by the water
heat change is mass * delta T * spec heat
Let the spec heat of the metal be z.
47.5(300-40)z = 75(40-22)(4.18)
z = 0.457
Looks like the metal is most likely iron.