Posted by **Chris** on Friday, December 16, 2011 at 5:26am.

Damon, Help :)

A rancher plans to set aside a rectangular region of one square kilometer for cattle and wishes to build a wooden fence to enclose the region. Since one side of the region will run along the road, the rancher decides to use a better quality wood for that side which costs three times as much as the wood for the other sides. What dimensions will minimize the cost of the fence?

You answered:

x y = 1

c = 3 x + x + 2 y = 4 x + 2 y

c = 4 x + 2/x

dc/dx = 4 - 2/x^2

= 0 for minimum

4 = 2/x^2

x^2 = 1/2

x = 1/sqrt 2 = sqrt 2/2 along road

y = sqrt 2

Now I have a stupid question... what happened to the y in the c= equations?

- Calculus -
**Damon**, Friday, December 16, 2011 at 5:30am
x y = 1

so

y = 1/x

## Answer This Question

## Related Questions

- Calculus - A rancher plans to set aside a rectangular region of one square ...
- calculus - Damon help again :) (last one I promise) why is X along the road ...
- Calculus-Applied Optimization Quiz Problem - A rancher wants to fence in a ...
- Calculus - A rancher wants to fence in an area of 500000 square feet in a ...
- Calculus - A rancher wants to fence in an area of 5189400 square feet in a ...
- math - A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock...
- math - A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock...
- Calc - A rancher wants to fence in an area of 1500000 square feet in a ...
- CALC - A rancher wants to fence in an area of 1500000 square feet in a ...
- math - A farmer plans to enclose a rectangular region, using part of his barn ...

More Related Questions