Posted by Matt on Friday, December 16, 2011 at 12:57am.
Let d be the distance from the drop point to the top of the window.
The time to reach the top is
t = sqrt(2d/g)
The time to reach the bottom is
t' = t + 0.220 = sqrt[2(d+1.14)/g]
= sqrt(2d/g) + 0.22
It's rather messy, but there you have one equation in the single unknown, d. Solve for d.
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