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December 22, 2014

December 22, 2014

Posted by **Daniel** on Friday, December 16, 2011 at 12:36am.

x = 6sin(t), y = t^2 + t; (0,0)

How do I do this without the value of t? I don't see a way to eliminate the parameter.

- calculus -
**Daniel**, Friday, December 16, 2011 at 12:46amOh also if you can, how do you find d2y/d2x for parametrics?

- calculus -
**Steve**, Friday, December 16, 2011 at 1:01pmThe nice thing about parametric equations is that you don't have to eliminate the parameter.

dy/dx = dy/dt / dx/dt

dy/dx = (2t+1)/6cos(t)

This is zero at t = -1/2 and has a vertical asymptote whenever t = an odd multiple of pi/2.

The graph is a kind of double wave sine surve. It wanders back and forth in the x direction, but the escillations get longer in the y direction, since y uses t^2, instead of just t.

Mosey on over to wolfram dot com to see the big picture. Type in a command like

graph x=6*sin(t), y=t^2 + t, t=-5..5

try

graph x=6*sin(t), y=t^2 + t, t=-2..1.5 to see the horizontal tangent at t=-1/2

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