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September 30, 2014

September 30, 2014

Posted by **Sandra** on Thursday, December 15, 2011 at 8:43pm.

I came up with sigma in the middle

3 on top

j=0 on the bottom

2n+4 to the right of the signma sign

2. Find the 10th term of the sequence

-1/5,-1/20,-1/80 this was a geometric sequence so I said a(subscript10) = -1/5*1/4^(10-1)

=-1/5*(1/4)^9 = -1/5*1/2621444

= -1/1310702

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