Posted by **Ashley A.** on Thursday, December 15, 2011 at 8:28pm.

The cost, in millions, to remove x% of pollution in a pond is modeled by the equation:

C=6350/(425-3x)

.

What is the cost to remove 75% of the pollution?

Hint: Plug in and calculate, do not convert to a decimal.

Can someone tell me how figure this out step by step recheck my answer PLEASEEEEEE!!! I tried to recheck AND IT DIDN'T COME UP WITH SAME Answer due tommorrow help me please

cost = 6350/(425 - 3(.25)) =$ 14.967

it would cost about $15 million

- Algebra -
**bobpursley**, Thursday, December 15, 2011 at 8:34pm
you should have 75 in the denominator, not .25

cost = 6350/(425-225)= you do it.

- Algebra -
**Ashley A.**, Thursday, December 15, 2011 at 8:44pm
The answer would be 31.496 AM I CORRECT IT WOULD COST ABOUT 31 MILLION

## Answer this Question

## Related Questions

- Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...
- Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...
- Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled...
- Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...
- Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled...
- Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...
- Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...
- Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...
- Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...
- Algebra - 1. The cost, in millions of dollars, to remove x % of pollution in a ...

More Related Questions