Sunday

March 1, 2015

March 1, 2015

Posted by **JOSHUA** on Thursday, December 15, 2011 at 6:02pm.

C=6350/(425-3x)

.

What is the cost to remove 75% of the pollution?

Hint: Plug in and calculate, do not convert to a decimal.

Can someone tell me how figure this out step by step recheck my answer PLEASEEEEEE!!! I tried to recheck AND IT DIDN'T COME UP WITH SAME Answer due tommorrow help me please

cost = 6350/(425 - 3(.25)) =$ 14.967

it would cost about $15 million

- Algebra -
**Henry**, Saturday, December 17, 2011 at 4:22pmC = 6350 / (425 - 3x). x = 75%.

DO NOT CONVERT THE % TO DECIMAL!

C = 6350 / (425-3*75),

C = 6350 / (425-225),

C = 6350 / 200 = $31.75 M.

**Answer this Question**

**Related Questions**

Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...

Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...

Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled...

Algebra - The cost, in millions, to remove x% of pollution in a pond is modeled ...

Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...

Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...

Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...

Algebra - c=6350/(425-3x) What is the cost and equation to remove 99% of the ...

Algebra - 1. The cost, in millions of dollars, to remove x % of pollution in a ...

ALGEBRA - 1. The cost, in millions of dollars, to remove x % of pollution in a ...