physics
posted by dan on .
What is the pressure at the bottom of a river (12 m deep) if the air pressure over the river is 98.23 kPa? The density of the river water is 988 kg/m3.

P = (rho)*g*(depth) + Po
rho is the density of the water
depth = 12 m
g = 9.8 m/s^2
Po = 98.23*10^3 N/m^2
Solve for P