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What is the pressure at the bottom of a river (12 m deep) if the air pressure over the river is 98.23 kPa? The density of the river water is 988 kg/m3.

  • physics - ,

    P = (rho)*g*(depth) + Po

    rho is the density of the water
    depth = 12 m
    g = 9.8 m/s^2
    Po = 98.23*10^3 N/m^2

    Solve for P

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