physics
posted by Tim on .
radius of the earth = 6.37 × 10^6
what is the speed of a 90.6 kg person at the equator?
I know that F=m(v^2/r) but I don't know the force. Is there another equation that I'm missing or I'm using the wrong one?
Thanks

They are not asking for the force. They want the speed due to the rotation of the earth. That equals R*w.
R is the earth radius and w is its rotation rate in radians per second. 
How would I know W if that wasn't given?

So I figured this out myself a=v^2/r
which is also equal to (4pi^2*r^2)/T^2
and T is 86400 secs which is how long it takes for a day to pass