How many kcal of heat are required to vaporize 25.0 kg of water at 100C?
To find out how many kcal of heat are required to vaporize 25.0 kg of water at 100°C, we need to use the formula for calculating the heat required to vaporize a substance:
Q = m * ΔHvap
where:
Q = heat energy required (in kcal)
m = mass of the substance (in kg)
ΔHvap = heat of vaporization (in kcal/kg)
To find the heat of vaporization for water, we need to refer to a reliable source or use the commonly accepted value of 540 kcal/kg at 100°C.
Now we can plug in the values into the formula:
Q = 25.0 kg * 540 kcal/kg
Q = 13,500 kcal
Therefore, it would take 13,500 kcal of heat to vaporize 25.0 kg of water at 100°C.