Posted by **Albert** on Thursday, December 15, 2011 at 3:46pm.

A rectangle field with area of 1,500,000 needs to be fenced. 2W+2L=5,000. solve for L and W

- College Algebra -
**Reiny**, Thursday, December 15, 2011 at 5:19pm
so you would have

WL = 1500000

and W+L = 2500

or L = 2500-W

back into the 1st...

W(2500-W) = 1500000

-w^2 + 2500W - 1500000 = 0

w^2 - 2500W + 1500000=0

(W-1500)(W - 1000) = 0

W = 1500 or W = 1000

If W = 1500, then L = 1000

I W = 1000 , then L = 1500

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