For the balanced equation shown below, how many moles of C4H10O reacted, if 0.5599 moles of H2O are produced?
C4H10O+6O2 --> 4CO2+5H2O
All of your posts are the same concept.
To determine the number of moles of C4H10O reacted, we will use the balanced equation and the given information about the moles of H2O produced.
According to the balanced equation, for every mole of C4H10O reacted, 5 moles of H2O are produced. Therefore, there is a 5:1 ratio between the moles of H2O and C4H10O.
Given that 0.5599 moles of H2O are produced, we can use this ratio to find the moles of C4H10O. We can set up a proportion using the ratio:
0.5599 moles H2O / 5 moles H2O = x moles C4H10O / 1 mole C4H10O
Simplifying the proportion:
0.5599 moles H2O * 1 mole C4H10O = 5 moles H2O * x moles C4H10O
Rearranging the equation to solve for x:
x moles C4H10O = (0.5599 moles H2O * 1 mole C4H10O) / 5 moles H2O
Calculating the moles of C4H10O:
x moles C4H10O = 0.11198 moles C4H10O
Therefore, 0.11198 moles of C4H10O reacted.