what mass of KCl in grams is formed with 20 lbs of KClO3 is decomposed
KCl03 yields KCl + O2
Here is a worked example with KClO3.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To find the mass of KCl formed when 20 lbs of KClO3 is decomposed, we need to use stoichiometry.
1. Firstly, we need to convert pounds (lbs) to grams (g). Since 1 lb is equal to approximately 453.59 g, we can multiply 20 lbs by this conversion factor:
20 lbs * 453.59 g/lb = 9071.8 g
2. Next, we need to determine the molar ratio between KClO3 and KCl using the balanced chemical equation:
KClO3 yields KCl + O2
From the balanced equation, we see that the molar ratio between KClO3 and KCl is 1:1. This means that for every 1 mol of KClO3, we will have 1 mol of KCl.
3. Now, we need to calculate the molar mass of KClO3 (potassium chlorate) and KCl (potassium chloride). The molar mass can be found by summing the atomic masses of each element present in the compound. The atomic masses are found on the periodic table.
- Molar mass of KClO3:
Potassium (K) = 39.10 g/mol
Chlorine (Cl) = 35.45 g/mol
Oxygen (O) = 16.00 g/mol (there are three oxygen atoms in KClO3)
Total molar mass = (39.10 g/mol) + (35.45 g/mol) + (16.00 g/mol * 3) = 122.55 g/mol
- Molar mass of KCl:
Potassium (K) = 39.10 g/mol
Chlorine (Cl) = 35.45 g/mol
Total molar mass = (39.10 g/mol) + (35.45 g/mol) = 74.55 g/mol
4. Now, we can calculate the number of moles of KClO3 using its molar mass and mass in grams:
Moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
= 9071.8 g / 122.55 g/mol
≈ 74.04 mol
5. Since the molar ratio between KClO3 and KCl is 1:1, the number of moles of KCl formed will also be 74.04 mol.
6. Finally, we can find the mass of KCl (potassium chloride) by multiplying the number of moles by its molar mass:
Mass of KCl = Moles of KCl * Molar mass of KCl
= 74.04 mol * 74.55 g/mol
≈ 5516.11 g
Therefore, approximately 5516.11 grams of KCl will be formed when 20 lbs (9071.8 grams) of KClO3 is decomposed.