Posted by Anonymous on Thursday, December 15, 2011 at 2:58am.
A ball is thrown with an initial velocity of 20 meters per second at an angle of 60° with the horizontal ground surface. Find the following:
a. the horizontal velocity of the ball
b. the ball’s initial vertical velocity
c. the range of the ball
d. the maximum height of the ball

physics  Henry, Saturday, December 17, 2011 at 3:36pm
Vo = 20 m/s @ 60 Deg.
a. Xo = 20*cos60 = 10 m/s.
b. Yo = 20*sin60 = 17.3 m/s.
c. Tr = (Vf  Vo) / g,
Tr = (0  17.3) / 9.8 = 1.77 s. = Rise
time.
Tf = Tr = 1.77 s.
Tr + Tf = Time in flight.
R = Xo * (Tr+Tf),
R = 10 m/s. * (1.77+1.77) s. = 35.4 m.
= Range.
d. h max = (Yf^2  Yo^2) / 2g,
h max = (0  (17.3)^2) / 19.6=15.31 m
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