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November 27, 2014

November 27, 2014

Posted by **Anonymous** on Thursday, December 15, 2011 at 2:54am.

- physics -
**tchrwill**, Thursday, December 15, 2011 at 3:35pmThe acceleration due to gravity derives from g = µ/R^2 where

G = the acceleration due to gravity

µ = the earths gravitational constant = GM

G = the universal gravitational constant = 6.67259x10^-11

M = the mass of the earth = 5.97424x10^24

R = the mean surface radius of the earth = 6378km

Therefore, g = 6.67259x10-11(5.97424x10^24)/6,378,000^2

……………..= 9.7995m/sec^2

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