Thursday

March 5, 2015

March 5, 2015

Posted by **Anonymous** on Thursday, December 15, 2011 at 2:54am.

- physics -
**tchrwill**, Thursday, December 15, 2011 at 3:35pmThe acceleration due to gravity derives from g = µ/R^2 where

G = the acceleration due to gravity

µ = the earths gravitational constant = GM

G = the universal gravitational constant = 6.67259x10^-11

M = the mass of the earth = 5.97424x10^24

R = the mean surface radius of the earth = 6378km

Therefore, g = 6.67259x10-11(5.97424x10^24)/6,378,000^2

……………..= 9.7995m/sec^2

**Answer this Question**

**Related Questions**

Physics - A. Use the relation 2 m m m GM g R ƒ to find the acceleration due to ...

physics/math - Calculate the magnitude of the gravitational force between the ...

physics - Calculate the magnitude of the gravitational force between the Earth ...

Physics - At the heighest point on earth, the distance to the center of the ...

physics - Find the distance (measured in earth radii, RE) from the center of the...

physcial science - How do I calculate the orbital velocity of a satellite that ...

precalculus - The acceleration acting on a falling object due to gravity varies ...

Physics - What is the distance from the Earth's center to a point outside the ...

physics - What is the distance from the Earth's center to a point outside the ...

physics - What is the distance from the Earth's center to a point outside the ...