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April 24, 2014

April 24, 2014

Posted by **Simon** on Wednesday, December 14, 2011 at 4:32pm.

v2= (0,1,3,3)

v3= (1,-1,-4,-5)

v4= (1,0,-2,-4)

a) Let U=span{v1,v2,v3,v4}. Find the dimension of U

b) Is span {v1,v2,v3,v4}=R4?

c) Find a basis for U

Very Much Appreciated!!!

- Linear Algebra -
**MathMate**, Wednesday, December 14, 2011 at 11:52pmIf U=span(v1,v2,v3,v4), then check the rank of the matrix

1 1 2 1

0 1 3 3

1 -1 -4 -5

1 0 -2 -4

(the v's are in rows)

The rank of the matrix is the dimension of U.

This can be done by reducing the matrix to the echelon form. The number of non-zero pivots is the rank of the matrix.

Do you need help with the reduction to the echelon form?

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