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algebra

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the stopping distance d of a car after the brakes are applied varies directly as the square of the speed r if a car travelling 80mph can stop in 360ft, how many feet will it take the same car to stop when it is travelling 70mph

  • algebra -

    d ∝v^2
    d = k v^2
    for the given...
    360 = k(80)^2
    k = 360/6400
    = 9/160

    so if v = 70
    d = (9/160)(4900) = 275.625 ft

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