Posted by Anonymous on Tuesday, December 13, 2011 at 6:19pm.
if C'(x) = 3x^2 - 36x + 120
then
C(x) = x^3 - 18x^2 + 120x + c , (I integrated)
if x=1 then C(1) = 5
5 = 1 - 18 + 120 + c
c = -98
C(x) = x^3 - 18x^2 + 120x - 98
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