Posted by michael on Tuesday, December 13, 2011 at 1:43pm.
a ladder leaning against a wall makes a 60 degree angle with the ground. the base of the ladder is 4m from the building. how high above the ground is the top of the ladder?

math  Reiny, Tuesday, December 13, 2011 at 1:46pm
tan 60° = height/4
height = 4tan60 = .....

math  michael, Tuesday, December 13, 2011 at 2:25pm
problem im on online schooling and its a special right triangles assignment and i don't have a calculator do to tangent and all that so that's why i need help.

math  Reiny, Tuesday, December 13, 2011 at 2:41pm
You should really get yourself a scientific calculator.
You can now get them around $10, I have seen them sell at about $5
Secondly you should memorize the ratio of sides of the standard 30690 and the 454590 rightangled triangles, in this case this is what they probably expected
the sides opposite the 306090 are 1 , √3, 2
and for the 454590 the sides are 1, 1, √2
so tan 60 = √3/1
=1.7321
so height = 4(1.7321) = 6.93 appr

math  anon, Monday, July 23, 2012 at 4:41pm
short leg = 4; to find long leg multiply 4 x 2; long leg = 8; to find how high; use x^2 + 4^2 = 8^2
so: x^2 + 16 = 64; subtract 16 from both sides: x^2 = 48; find the square root of 48; x = 6.93 so the top of the ladder is 6.93 m above the ground.
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