Posted by **michael** on Tuesday, December 13, 2011 at 1:43pm.

a ladder leaning against a wall makes a 60 degree angle with the ground. the base of the ladder is 4m from the building. how high above the ground is the top of the ladder?

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**Reiny**, Tuesday, December 13, 2011 at 1:46pm
tan 60° = height/4

height = 4tan60 = .....

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**michael**, Tuesday, December 13, 2011 at 2:25pm
problem im on online schooling and its a special right triangles assignment and i dont have a calculator do to tangent and all that so thats why i need help.

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**Reiny**, Tuesday, December 13, 2011 at 2:41pm
You should really get yourself a scientific calculator.

You can now get them around $10, I have seen them sell at about $5

Secondly you should memorize the ratio of sides of the standard 30-6-90 and the 45-45-90 right-angled triangles, in this case this is what they probably expected

the sides opposite the 30-60-90 are 1 , √3, 2

and for the 45-45-90 the sides are 1, 1, √2

so tan 60 = √3/1

=1.7321

so height = 4(1.7321) = 6.93 appr

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**anon**, Monday, July 23, 2012 at 4:41pm
short leg = 4; to find long leg multiply 4 x 2; long leg = 8; to find how high; use x^2 + 4^2 = 8^2

so: x^2 + 16 = 64; subtract 16 from both sides: x^2 = 48; find the square root of 48; x = 6.93 so the top of the ladder is 6.93 m above the ground.

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