Posted by Sarah on .
I'm doing test corrections, and it's been a few weeks since we did this, so I'm a little fuzzy. I'm supposed to find the zeros, relative extrema, and inflection points of f(x) = x^3  6x^2 + 3x + 10.
The zeros would be 1, 2, and 5 right?
Then I would take the derivative of that and get that f'(x)=3x^212x+3.
Then what do I do from here? I vaguely remember something about finding critical points using intervals, but I don't really remember how to do that. Do I maybe need the second derivative?

Calculus 
Steve,
f has a max/min where f'=0 and f''≠0
f is increasing where f' > 0
f is concave up where f'' > 0
f has an inflection point where f'' = 0