Posted by **Lynn** on Tuesday, December 13, 2011 at 11:11am.

Solve by completing the square:

x^2-6x+3=0

please take me step by step

- Algebra -
**Steve**, Tuesday, December 13, 2011 at 12:54pm
Remember that (a-b)^2 = a^2 - **2ab** + b^2

So, if you have x^2 - 6x you need half of the 6 to complete the square:

x^2 - 6x + 9 - 9 + 3 = 0

(x-3)^2 - 6 = 0

(x-3)^2 = 6

So, you can see that

x-3 = ±√6

so,

x = 3 ± √6

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