Posted by Henry on Monday, December 12, 2011 at 9:15pm.
Draw line BF, perpendicular to AC
/_GAC = 30º and /_ABG = 30º
AG = GC = 1
AB=1/cos30º=2/sqrt3 BC = CD = DE = EF = FA
BG = ABsin30º = 1/sqrt3
Perimeter P = 6AB
Area = (2)/sqrt3 + 2(2)/sqrt3
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