Posted by **Tabitha** on Monday, December 12, 2011 at 10:31am.

Please check these:

1.When the fraction 2/3 is used as exponent, wht role does the denominator 3 play in evaluating expression? I think it indicates cube root of the base,correct?

2.sqrt of (2^4x/4^-2x) is equilvalent to 2^4x, correct?

3.Simplify (2xy^-2z^4/y^-3/z^3)^2 would be 4x^2y^2z^2,correct?

4. (4x^2y^-4z)^3 simplified would be 64x^6z^3/y^12, correct

Thank you

- Algebra-please check -
**Reiny**, Monday, December 12, 2011 at 10:51am
1, correct

2. correct, good job on that one

3. not sure about the priority of the two divisions

I think the whole thing is squared, but you will need some additional brackets in that denominator

the way you typed it , it would be

[(2xy^-2 z^4) ( 1/y^-3) ( 1/z^3) ]^2 = 4x^2 y^2 z^2 which is your answer

OK then!

4. good again!

- Algebra-please check -
**Tabitha**, Monday, December 12, 2011 at 3:00pm
Thank you

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