Posted by Tabitha on Monday, December 12, 2011 at 10:31am.
1, correct
2. correct, good job on that one
3. not sure about the priority of the two divisions
I think the whole thing is squared, but you will need some additional brackets in that denominator
the way you typed it , it would be
[(2xy^-2 z^4) ( 1/y^-3) ( 1/z^3) ]^2 = 4x^2 y^2 z^2 which is your answer
OK then!
4. good again!
Thank you
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