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November 28, 2014

November 28, 2014

Posted by **fareha** on Monday, December 12, 2011 at 5:13am.

- calculus -
**drwls**, Monday, December 12, 2011 at 5:42am25 - 25 - 50

Maximum Area = 1250 ft^2

How to get that answer:

Let x be the side length that is used twice. The side parallel to the existing fence then has length 100 - 2x.

The area A is then

A(x) = x*(100 - 2x) = 100 x - 2x^2

dA/dx = 0 when

100 = 4x

x = 25

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