Thursday

August 21, 2014

August 21, 2014

Posted by **fareha** on Monday, December 12, 2011 at 5:13am.

- calculus -
**drwls**, Monday, December 12, 2011 at 5:42am25 - 25 - 50

Maximum Area = 1250 ft^2

How to get that answer:

Let x be the side length that is used twice. The side parallel to the existing fence then has length 100 - 2x.

The area A is then

A(x) = x*(100 - 2x) = 100 x - 2x^2

dA/dx = 0 when

100 = 4x

x = 25

**Related Questions**

algebra - A farmer decides to enclose a rectangular garden, using the side of a ...

College Cal 1 - A farmer wants to fence off a rectangular field of area 15000 ...

calculus - a farmer wishes to fence off a rectangular plot of land, using an ...

Pre Calculus - A contractor is to fence off a rectangular field along a straight...

Calculus - The Regional Farm Bureau (RFB) is preparing a brochure that offers ...

Calculus - The Regional Farm Bureau (RFB) is preparing a brochure that offers ...

intermediate algebra - A farmer with 3000 feet wants to enclose a rectangular ...

Math - Jennifer plans to fence a rectangular area around her rectangular ...

Calculus - Optimization - A fence is to be built to enclose a rectangular area ...

intermediate algebra - A farmer with 3000 feet of fencing wants to enclose a ...