calculus
posted by john on .
A tank with a rectangular base and rectangular sides is to be open at the top. It is to be constructed so that its width is 4 meters and its volume is 36 cubic meters. Building the tank costs $10 per square meter for the base and $5 per square meter for the sides.
a) Write a function C, the cost of constructing the described tank as a function of l(the length) and h(the height).
b) Write a function C, the cost of constructing the described tank as a function of a single variable.
c) What is the cost of the least expensive tank? (show all work)

let its length be l m
and its height by h m
volume = 4lh
but 4lh = 36
h = 9/l
a) cost = 10(4l) + 5(2lh) + 5(8h)
= 40l + 10lh + 40h
b) cost = 10(4l) + 5(2l)(9/l) + 40(9/l
= 40l + 90 + 360/l ,where l ≠ 0
c) d(cost)/dl = 40 + 0  360/l^2 = 0 for a min of cost
40 = 360/l^2
l^2 = 9
l = √9 = 3
when l = 3, h = 9/3 = 3
dimensions for min cost = 3by4 for the base and a height of 3
cost = 330.00
test: take a value slightly higher and lower than l = 3
l = 3.1, cost = 330.13 , higher
l = 2.9 , cost = 330.14 , higher
answer looks good