2H2 (g) O2 (g) --> 2H2O (g) if 44 g of O2 are reacted , determine the amount if heat transferred in the reaction when the Heat = -483.6 kJ
The way you have posed the question is confusing. I recommend that you rephrase the question and re-post at the top of the page.
To determine the amount of heat transferred in the reaction, you need to calculate the heat of reaction per gram of O2 reacted.
First, let's find the molar mass of O2:
Oxygen has a molar mass of approximately 16 g/mol. Since there are two oxygen atoms in one O2 molecule, the molar mass of O2 is 2 * 16 g/mol = 32 g/mol.
Next, let's calculate the number of moles of O2 used in the reaction:
Number of moles = mass / molar mass
Number of moles = 44 g / 32 g/mol = 1.375 mol
Now, we can determine the amount of heat transferred per mole of O2 reacted:
Heat per mole = Heat / moles
Heat per mole = -483.6 kJ / 1.375 mol = -352.152 kJ/mol
Finally, we can determine the amount of heat transferred for the given mass of O2 (44 g):
Heat transferred = Heat per mole * moles
Heat transferred = -352.152 kJ/mol * 1.375 mol = -483.6 kJ
Therefore, when 44 g of O2 are reacted, the amount of heat transferred in the reaction is -483.6 kJ.