An electric motor develops 73 kW of power as it lifts a loaded elevator 20.0 m in 35 s. How much force does the motor exert?

P = FV,

F = P/V = (73,000) / (20 m / 35s) = 127,750 N.

To find the force exerted by the motor, we can use the formula:

Power = Force * Velocity

Given that the power developed by the motor is 73 kW (kilowatts), we can convert it to watts by multiplying by 1000:

Power = 73 kW * 1000 = 73,000 W

We also know that the elevator is lifted a distance of 20.0 m in a time of 35 s. So, we can calculate the velocity using the formula:

Velocity = Distance / Time

Velocity = 20.0 m / 35 s = 0.5714 m/s (rounded to four decimal places)

Now, with the power (73,000 W) and velocity (0.5714 m/s), we can rearrange the formula to solve for force:

Force = Power / Velocity

Force = 73,000 W / 0.5714 m/s = 127,567.66 N (rounded to two decimal places)

Therefore, the motor exerts a force of approximately 127,567.66 Newtons.