After a day of testing race cars, you decide to take your own 1540-kg car onto the test track. While moving down the track at 12 m/s, you suddenly accelerate to 27 m/s in 9 s. What is the average net force that you have applied to the car during the 9-s interval?
a=(v-v₀)/t
F=ma
To calculate the average net force applied to the car during the 9-second interval, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = m * a).
First, let's find the change in velocity by subtracting the initial velocity from the final velocity: Δv = 27 m/s - 12 m/s = 15 m/s.
Next, we can use the formula for average acceleration: a = Δv / t, where a is the average acceleration, Δv is the change in velocity, and t is the time interval. Plugging in the values, we get: a = 15 m/s / 9 s ≈ 1.67 m/s^2.
Finally, we can calculate the average net force using Newton's second law: F = m * a, where F is the average net force, m is the mass of the car, and a is the average acceleration. Plugging in the values, we get: F = 1540 kg * 1.67 m/s^2.
Calculating this, we find that the average net force applied to the car during the 9-second interval is approximately 2573.8 N.