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precalculus

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find the increasing and decreasing intervals of 4x^3-7x+3

  • precalculus - ,

    f = 4x^3 - 7x + 3
    = (x-1)(2x-1)(2x+3)

    If you've started working with derivatives yet, then you know that where f' > 0, f is increasing

    f' = 12x^2 - 7

    find where f' >0 and that will tell you where f is increasing.

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