Posted by **ck** on Sunday, December 11, 2011 at 7:54pm.

find the increasing and decreasing intervals of 4x^3-7x+3

- precalculus -
**Steve**, Monday, December 12, 2011 at 6:27pm
f = 4x^3 - 7x + 3

= (x-1)(2x-1)(2x+3)

If you've started working with derivatives yet, then you know that where f' > 0, f is increasing

f' = 12x^2 - 7

find where f' >0 and that will tell you where f is increasing.

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