Posted by **Allison** on Sunday, December 11, 2011 at 7:42pm.

If m<DBC=10x and m<ACb=4x^2, find m<ACB.

The quadrilateral ABCD is a rectangle.

B ------------- C

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A -------------|D

There are diagonal bisectors inside the rectangle but I could not draw them in. The diagonals are DB and CA and the point in the middle is E.

- Geometry -
**Steve**, Monday, December 12, 2011 at 6:19pm
Let E be where the diagonals intersect.

Since ABCD is a rectangle, the diagonals are the same length, and bisect each other.

Thus, EB = EC and the triangle BCE is isosceles, making m<DBC = m<ACB

So,

10x = 4x^2

10 = 4x

x = 5/2 = 2.5

<DBC = 25°

<ACB = 25°

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