Posted by **Allison** on Sunday, December 11, 2011 at 7:42pm.

If m<DBC=10x and m<ACb=4x^2, find m<ACB.

The quadrilateral ABCD is a rectangle.

B ------------- C

| |

| |

| |

| |

A -------------|D

There are diagonal bisectors inside the rectangle but I could not draw them in. The diagonals are DB and CA and the point in the middle is E.

- Geometry -
**Steve**, Monday, December 12, 2011 at 6:19pm
Let E be where the diagonals intersect.

Since ABCD is a rectangle, the diagonals are the same length, and bisect each other.

Thus, EB = EC and the triangle BCE is isosceles, making m<DBC = m<ACB

So,

10x = 4x^2

10 = 4x

x = 5/2 = 2.5

<DBC = 25°

<ACB = 25°

## Answer this Question

## Related Questions

- math - In rectangle ABCD, shown here, ACB measures 30° and. CD = 40 mm. ...
- geometry - in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x...
- geometry - Quadrilateral RSTU is a rectangle with diagonal RT. If m = 8x + 4 and...
- geometry - What is the most precise name for quadrilateral ABCD with vertices A...
- geometry - The diagonal of a rectangle measures 26 cm the width of the rectangle...
- geometry - Given: QRST is a parallelogram. Prove: QRST is a square. Complete ...
- geometry - Rectangle ABCD has diagonals AC and BD. If the diagonal lengths are ...
- Math - In the accompanying diagram, abcd is a rectangle with ab as a diameter of...
- geometry - A dartboard consists of a circle inside a rectangle. the diameter of ...
- maths - Given is a quadrilateral ABCD,diagonals AC and BDare such that AO=BO=CO=...