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March 30, 2017

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If m<DBC=10x and m<ACb=4x^2, find m<ACB.
The quadrilateral ABCD is a rectangle.
B ------------- C
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A -------------|D
There are diagonal bisectors inside the rectangle but I could not draw them in. The diagonals are DB and CA and the point in the middle is E.

  • Geometry - ,

    Let E be where the diagonals intersect.
    Since ABCD is a rectangle, the diagonals are the same length, and bisect each other.

    Thus, EB = EC and the triangle BCE is isosceles, making m<DBC = m<ACB

    So,
    10x = 4x^2
    10 = 4x
    x = 5/2 = 2.5

    <DBC = 25°
    <ACB = 25°

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