Posted by Allison on Sunday, December 11, 2011 at 7:42pm.
If m<DBC=10x and m<ACb=4x^2, find m<ACB.
The quadrilateral ABCD is a rectangle.
B ------------- C
There are diagonal bisectors inside the rectangle but I could not draw them in. The diagonals are DB and CA and the point in the middle is E.
Geometry - Steve, Monday, December 12, 2011 at 6:19pm
Let E be where the diagonals intersect.
Since ABCD is a rectangle, the diagonals are the same length, and bisect each other.
Thus, EB = EC and the triangle BCE is isosceles, making m<DBC = m<ACB
10x = 4x^2
10 = 4x
x = 5/2 = 2.5
<DBC = 25°
<ACB = 25°
Answer This Question
More Related Questions
- math - In rectangle ABCD, shown here, ACB measures 30° and. CD = 40 mm. ...
- geometry - in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x...
- Math - geometry- On the coordinate plane, draw a rectangle ABCD with vertices at...
- Geometry - Quadrilateral EFGH is a rectangle. If EM equals 5X plus one and HF ...
- Geometry - If the width of rectangle ABCD is 8 cm and the length of diagonal ...
- geometry - Quadrilateral RSTU is a rectangle with diagonal RT. If m = 8x + 4 and...
- geometry - What is the most precise name for quadrilateral ABCD with vertices A...
- college geometry - A rectangle ABCD has three of its vertices at A(2, 1), B(6, 1...
- geometry - The diagonal of a rectangle measures 26 cm the width of the rectangle...
- geometry - Given: QRST is a parallelogram. Prove: QRST is a square. Complete ...