Posted by james on Sunday, December 11, 2011 at 7:20pm.
Just lay out the points on the line
BD contains the right half of BC and the left half of CE
So, what's left is the same length: The left half of AC and the right half of CE
AE = AB + BC + CD + DE
but BD = BC + CD = 14
so,
AE = AB + 14 + DE
However,
AB = BC and CD = DE so AB+DE = BC+CD = 14
AE = 14 + 14 = 28
With that in hand, the 2nd problem should be trivial.
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