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Posted by on Sunday, December 11, 2011 at 6:58pm.

The specific heat of pure water at 15 degrees celsius is 4184j/(kg.k). Convert this to kcal/(kg.k).
pls help

  • physics - , Sunday, December 11, 2011 at 7:05pm

    4184j/kgK ( 1K/1C)(XXX Kcal/j)

    so, what is the conversion factor for Kcal to J?

    1 KCal= 4184joules

    4184j/kgK ( 1K/1C)(1Kcal/4184j)= ?

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