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March 28, 2015

March 28, 2015

Posted by **Danielle** on Sunday, December 11, 2011 at 6:38pm.

- algebra -
**Steve**, Monday, December 12, 2011 at 6:04pmLet n be the thousands of visitors

Let x be the number of years since 1990

n(x) then produces the number of visitors in any given year since 1990. We are told that in 2000 (10 years after 1990)

n(10) = 1529.6

n(x+10) = 1529.6 + 43.1x

That gives us the visitors for years after 2000. But we want to back up to 1990. SO substitute (x-10) for x to get

n(x-10+10) = 1529.6 + 43.1(x-10)

n(x) = 1529.6 + 43.1x - 431

n(x) = 1098.6 + 43.1x

Makes sense, since during the first 10 years, 431 visitors are added, making the count 1529.6 in 2000. And things just keep going from there.

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