Posted by **Clarissa ** on Sunday, December 11, 2011 at 6:24pm.

three people are trying to hold a lion still for the vet. The lion, in the center, is wearing a collar with three ropes attached to it and each person has a hold of the rope. charlie is pulling in the direction of 62 degrees west of north with a force of 175 newtons. Sam is pulling in the direction of 43 degrees east of north with a force of 200 newtons. What is the direction and magnitude of the force which must be exerted by Alice on the third rope to counterbalance Sam and Charlie?

- math / science -
**Henry**, Monday, December 12, 2011 at 8:14pm
Charlie: 175 N. @ 152 Deg.,CCW.

Sam: 200 N. @ 47 Deg.,CCW.

X = 175*cos152 + 200*cos47 = -18.1 N.

Y = 175*sin152 + 200*sin47 = 228.4 N.

Alice: Force must be equal and opposite

The vector sum of Charlie and Sam's force.

X = 18.1 N.

Y = -228.4 N.

tanA = Y/X = -228.4 / 18.1 = -12.61878.

A = -85.5 Deg. = 85.5 Deg S of E

A = -85.5 + 360 = 274.5 Deg.,CCW..

M = X / cosA = 18.1 / cos274,5 = 230.7 N.@ 274.5 Deg.

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