Post a New Question


posted by .

A spring has a force constant of 546.5 N/m.
Find the potential energy stored in the
spring when the spring is
a) stretched 4.18 cm from equilibrium.
Answer in units of J

  • Physics -

    (1/2)k x^2 = (1/2)(546.5)(.0418)^2
    = 0.477 Joules

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question