Posted by **Ivana** on Sunday, December 11, 2011 at 4:32pm.

A combination of 0.383 kg of water at 22.8◦C, 0.499 kg of aluminum at 61.3◦C, and 0.408 kg of copper at 68.3◦C is mixed in an insulated container and allowed to come to thermal equilibrium.

Determine the final temperature of the mix- ture.

- Physics- HELPPP -
**drwls**, Sunday, December 11, 2011 at 5:21pm
You first need to look up the specific heats of those three materials. Call then Cw (water), Ca (aluminum) and Cc (copper).

The heat gained by the water equals the leat lost by the other two materials.

0.383*Cw*(T-22.8) = (0.499)(Ca)*(61.3 - T) + 0.408*Cc*(68.3-T)

Substitute the C values and solve for the final temperature, T.

## Answer This Question

## Related Questions

- physics - If 50 g of ice at −5 ◦C is mixed into 300 g of water at 60...
- physics - A combination of .403 kg of water at 45.1 C, .471 kg of aluminum at 41...
- Chemistry - PLEASE HELP OR I WILL FAIL What would be the final temperature of ...
- Physics - A 0.0500 kg ice cube at -30.0◦C is placed in 0.400 kg of 35.0&#...
- Physics - A 0.0500 kg ice cube at -30.0◦C is placed in 0.400 kg of 35.0&#...
- AP Chemistry - What would be the final temperature of the system if 20 g of lead...
- Chemistry - (DrBob222 please help me) What would be the final temperature of the...
- PHYSICS!! - A 618 g sample of water at 73◦C is mixed with 478 g of water ...
- physics - A 46 g ice cube at 0◦C is placed in 988 g of water at 90◦C...
- Physics - What is the direction of this resultant vector (between the limits of...

More Related Questions