Posted by janee on Sunday, December 11, 2011 at 9:45am.
A satellite moves in a circular orbit around the Earth at a speed of 5.8 km/s.
Determine the satellite’s altitude above the surface of the Earth. Assume the Earth is a homogeneous sphere of radius 6370 km and mass 5.98 × 1024 kg. The value of the universal gravitational constant is 6.67259 × 10−11 N · m2/
the gravitational force is the centripetal force

physics  tchrwill, Sunday, December 11, 2011 at 10:07am
When orbiting at 5.8km/s:
From Vc = sqrt(µ/r) where Vc = the velocity of an orbiting body, µ = the gravitational constant of the earth and r the radius of the circular orbit,with µ = GM, G = the universal gravitational constant and M = the mass of the central body, the earth in this instant,
r = µ/Vc^2
= 6.67259x10^11(5.98x10^24)/5800^2
The altitude is therefore
(r  6370)/1000 km.
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