Physics
posted by Kate on .
A. Calculate the force on an alpha particle in an electric field E=Exm where E=3.6E4 N/C and x is a unit vector in the x direction. What is the direction of the force?
B. Calculate the acceleration of the alpha particle in this electric field. What is the direction of the acceleration?
For part A what I did was:
F=qE=2(1.60E19 C)(3.6E5N/C)=1.152E13 to the positive x direction
Part B.
a=qE/m
F=mg
m=F/g
m=1.17E14
a=1.602E19[1.15E13/1.17E14]
a=1.57E18 m/s^2 to the +x direction
Not sure of the first one but I think the second one is definately wrong.Please check.

Why did you change E from 3.6*10^4 N/C to 3.6*10^5 N/C?
In Part 2, a = qE/m is the correct equation, but I do not see why you then introduced g.
The mass of an alpha particle is wrong. It is about 6.67*10^27 kg