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February 1, 2015

February 1, 2015

Posted by **Jennifer** on Saturday, December 10, 2011 at 11:49pm.

- Chemistry -
**DrBob222**, Sunday, December 11, 2011 at 12:50amYou are supposed to look at the table and use the data to calculate the half life. How do you suppose we can do that if you don't show the table?

- Chemistry -
**Jennifer**, Sunday, December 11, 2011 at 10:29amThe table wasn't available

- Chemistry -
**Jennifer**, Sunday, December 11, 2011 at 10:32amcounts/min time(hours)

800 0

713 1

450 5

200 12

112 17

a. 5h

b. 6h

c. 12h

d. 99h

- Chemistry -
**DrBob222**, Sunday, December 11, 2011 at 2:52pmln(No/N) = kt

No = 800 in all cases.

N = values from table

k = solve for this

t = time in hours.

For example, the first one is

ln(800/713) = k(1 hour)

k = 0.115 if I didn't goof.

Do that for each time period and average the values. Then substitute into the following:

k = 0.693/t_{1/2}and solve for t_{1/2}.

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