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November 26, 2014

November 26, 2014

Posted by **Candice** on Friday, December 9, 2011 at 9:46pm.

Could you please show me the working out for this question?

The answer in the textbook is 16 sq cm.

Thanks!!!

- Maths -
**Reiny**, Friday, December 9, 2011 at 10:29pmMake a sketch showing the chord of 12 and the the two radii of 10.

I see an isosceles triangle. Draw an altitude from the centre to that chord, making two congruent right-angled triangles.

let the height be x, then x^2 + 6^2 = 10^2

x^2 = 100-36 = 64

x = √64 = 8

So the area of the large triangle, 10,10,12 is

(1/2) (12)(8) = 48 cm^2

We have to find the central angle of the sector.

Let each angle at the centre of the right-angled triangles be Ø

sinØ = 6/10 = .6

Ø = 36.87‡

and the central angle is 2Ø = 73.74°

area of whole circle = π(10)^2 = 100π

area of sector/100π = 73.74/360

area of sector = 64.35 cm^2

sooo, the segment is 64.35 - 48 = 16.35 cm^2

(I carried all decimals my calculator could hold and only rounded off the final answer.)

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