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March 4, 2015

March 4, 2015

Posted by **Rock** on Friday, December 9, 2011 at 8:09pm.

- Alg2 -
**Steve**, Saturday, December 10, 2011 at 5:16amFind the half-life of C14. Call it n years

2^(-t/n) < .005

-t/n < ln(.005)/ln(2) = -7.64

t > 7.64n

check: 2^-7.64 = .005013, so after 7.64 half-lives, we are down to .5% of the original.

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