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April 20, 2014

April 20, 2014

Posted by **diana** on Friday, December 9, 2011 at 8:05pm.

- calculus -
**Steve**, Saturday, December 10, 2011 at 5:12amvertical asymptotes where denominator is zero

By now you should know all about how 1st and 2nd derivatives tell you about critical points:

g' = t(5t+8)/(5t+4)^2

g'' = 32/(5t+4)^3

g has max/min where g'=0 and g'' not 0

g has inflection where g'' = 0

g increasing where g' > 0

g concave up where g'' > 0

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