posted by Jon .
A reversible heat engine operates between thermal reservoirs at 1000 K and 290 K. If 8610 J is extracted from the hot reservoir, how much work is done by the heat engine?
8610 (1000-290)/1000= what
ç = 1 - 290K/1000K = 0.29 = 29.0%
The thermal efficiency is defined as the amount of work done per amount of heat absorbed from hot reservoir or...
ç = W/Qh
so then you would just use
W = e*Qh
and plug in what you know
Hannah, reread the question. My response is correct. It does not ask for thermalefficiency.