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A reversible heat engine operates between thermal reservoirs at 1000 K and 290 K. If 8610 J is extracted from the hot reservoir, how much work is done by the heat engine?

  • Physics -

    8610 (1000-290)/1000= what

  • Physics -

    ç = 1 - 290K/1000K = 0.29 = 29.0%

    The thermal efficiency is defined as the amount of work done per amount of heat absorbed from hot reservoir or...
    ç = W/Qh

    so then you would just use
    W = e*Qh

    and plug in what you know

  • Physics -

    Hannah, reread the question. My response is correct. It does not ask for thermalefficiency.

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